-->
Search the ArchivesNavigationContact InformationThe Citizen Newspapers For Advertising Information Email us your news! For technical difficulties |
Mixer it was not intuativeI did not find this intuitive, nor high school level. I bow to your high school. I admit I find it difficult to apply the right hand rule trying to figure out the positive and negative field calculations to the flow of B-field calculations. Since the currents are flowing in opposite directions the B-fields act against each other and are therefore additive. However, assuming a 2-D representation, and assuming a plane through the center of the wires parallel to the direction of the current flow. B= mu*I/(2*pi*r) where mu is the permeability of free space, which is a constant of 4*pi X 10^-7 T*m/A, I is the current in Amperes, and r is the radius of the B field (in meters) where you want the calculation. First, half of 1.1 inches is .55 inches, which is 0.01397 meters. (B field from wire 1) = mu*5.6/(2*pi*0.01397) = 8.4466 x 10^-5 T (B field from wire 2) = mu*16.6/(2*pi*0.01397) = 2.37625 x 10^-4 T I come up with 3.2209 x 10^-4 teslas. If I am right, I want a glass of a nice red wine. If not, I owe you a beer of your choice. Peace, and I ain't gonna do this one again. Locke's blog | login to post comments |